5q^2+22qr-15r^2=0

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Solution for 5q^2+22qr-15r^2=0 equation:


Simplifying
5q2 + 22qr + -15r2 = 0

Reorder the terms:
22qr + 5q2 + -15r2 = 0

Solving
22qr + 5q2 + -15r2 = 0

Solving for variable 'q'.

Factor a trinomial.
(5q + -3r)(q + 5r) = 0

Subproblem 1

Set the factor '(5q + -3r)' equal to zero and attempt to solve: Simplifying 5q + -3r = 0 Solving 5q + -3r = 0 Move all terms containing q to the left, all other terms to the right. Add '3r' to each side of the equation. 5q + -3r + 3r = 0 + 3r Combine like terms: -3r + 3r = 0 5q + 0 = 0 + 3r 5q = 0 + 3r Remove the zero: 5q = 3r Divide each side by '5'. q = 0.6r Simplifying q = 0.6r

Subproblem 2

Set the factor '(q + 5r)' equal to zero and attempt to solve: Simplifying q + 5r = 0 Solving q + 5r = 0 Move all terms containing q to the left, all other terms to the right. Add '-5r' to each side of the equation. q + 5r + -5r = 0 + -5r Combine like terms: 5r + -5r = 0 q + 0 = 0 + -5r q = 0 + -5r Remove the zero: q = -5r Simplifying q = -5r

Solution

q = {0.6r, -5r}

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